gfx.showmenu() and nested submenu bug? (FIXED)

[tack]

Hi all,

I am trying to construct a menu that looks like:

- Toplevel 1
   - Nested
         - Inner
- Toplevel 2

The menu syntax for showmenu() says to prefix the item with < to indicate it's the last item in a submenu. However above I want 'Inner' to terminate two submenus (Nested and Toplevel 1).

Near as I can tell, Reaper doesn't support this kind of structure? I have tried the obvious:

>Toplevel 1|>Nested|<<Inner|Toplevel 2

To no avail. The only workaround I could see is:

>Toplevel 1|>Nested|<Inner|<|Toplevel 2

But because of the empty item, there is a separator at the bottom of Submenu.

I think this could be fixed easily enough: just have |<| semantically mean terminate a submenu. This would also allow this grammar, equivalent to the above, which is superior IMO as it's more friendly to programmatic generation of the menu string.

>Toplevel 1|>Nested|Inner|<|<|Toplevel 2

[cfillion]

Use >< to make Nested the start of a submenu and the last one in its parent menu.

gfx.showmenu('>Toplevel 1|><Nested|<Inner|Toplevel 2')

[schwa]

We'll add this for 5.31, thanks.

gfx.showmenu(">first|>second|<third|<|first again")

(this essentially amounts to making sure the last item in a submenu is not a separator)

[tack]

Thanks cfillion. Indeed this does work, but I hope what won't discourage schwa from adding the support anyway because the way I suggested is significantly easier to programmatically build the menu string.

[tack]

Originally Posted by schwa

gfx.showmenu(">first|>second|<third|<|first again")

(this essentially amounts to making sure the last item in a submenu is not a separator)

But if for some reason you really wanted the last item to be a separator, you could do:

gfx.showmenu(">first|>second|third||<|<|first again")